2025-08-26
Setup
Consider a vector bundle
We can projectivise
By Leray-Hirsch, there is a surjection
There is a spectral sequence
which degenerates on
where
Exercise
Let
where this really means
where
Remark
This works for Grassmannian bundles as well. For example, if
where
The exercise implies that
Recall that we had
. We can the replace the equation with .- …
- Continue to get finally same thing but with equation
.
Other types
We have
This is not true integrally, but we only need to invert the worst primes to make it true.
Example:
Siegel parabolic:
Definition (Parabolic)
connected?
A parabolic subgroup is a subgroup that contains a Borel. The following are equivalent:
is parabolic. is proper. is projective.- There exists
such that
Exercise
Find
More on
We have
Notice that
So we have
is given by an intersection with a hyperplane.- It is a quadric hypersurface in
.
.
A symplectic form is a form on.
Fact: Given a smooth degree
hypersurface in : Intersecting a hypersurface with
generic hyperplanes gives points.
This implies that
Schubert varieties
Let
a Schubert cell. Topologically, these are all . a Schubert variety.
Theorem
Exercise
In type A, Schubert varieties have the following descriptions: Fix a flag
stable under
where
Remark
Example
Consider
- Longest root
. - Two reflections
and .
Look at action of
Implies